How do I get the DB2 date from a table in Julian format? I did write a query concatenating year and days, but it...
wasn't useful. It gave the SQL error -171. Please help.
SQL error -171 means "The SQL statement includes an unknown scalar function." Without seeing your query, I cannot tell what you did wrong. But never mind. I think the following will do it:
select year(thedate) , dayofyear(thedate) from yourtable
YEAR() and DAYOFYEAR() are DB2 scalar functions which return integers for the year and day of year (1-366), respectively. The day of year between 1 and 366 is what most people mean when they use the term "Julian."
If, instead of integers, you wanted a YYYYDDD string, you could use the CAST function:
select cast( year(thedate) * 1000 + dayofyear(thedate) as char(7) ) from yourtable
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