In MS SQL Server, I have a table with the following columns: DateTime, Item, Value. I need to write a query that...
returns the maximum and minimum value on each day of the current month for each item. In addition, the query must return the DateTime coincident with the maximum or minimum value. I am fairly new to SQL and although I do OK with the basics, I could use some help with this one.
Of course, there are always several legitimate ways to solve a SQL problem; especially for interesting problems like this. To solve the problem without the DateTime columns, the SQL is fairly simple, that is if you don't mind the somewhat inelegant way I've truncated the time from a DateTime.
select Item, convert(datetime,convert(varchar,DateTime,112)) as Day, min(Value) as minvalue, max(Value) as maxvalue from Items group by Item, convert(datetime,convert(varchar,DateTime,112))To get the actual DateTime values associated with the max and min values, I've embedded the original SQL in the FROM clause and included two in-line sub-queries in the SELECT clause.
select z.Item, z.minvalue, z.maxvalue, ( select DateTime from Items x where x.Item = z.Item and convert(datetime,convert(varchar,x.DateTime,112)) = z.Day and x.Value = z.minvalue ) as MinValueTime, ( select DateTime from Items y where y.Item = z.Item and convert(datetime,convert(varchar,y.DateTime,112)) = z.Day and y.Value = z.maxvalue ) as MaxValueTime from ( select Item, convert(datetime,convert(varchar,DateTime,112)) as Day, min(Value) as minvalue, max(Value) as maxvalue from Items group by Item, convert(datetime,convert(varchar,DateTime,112)) ) z
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