Using the SQL GROUP BY clause for counting combinations

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You've given very little information about your tables, so the following solution explains how to get the counts without going into details about how your tables are joined.

SELECT x.question_number
     , y.option_number
     , COUNT(*) AS number_of_rows
  FROM your joins go here
GROUP
    BY x.question_number
     , y.option_number

The count that is produced for this particular GROUP BY clause is the count for every single unique combination of question_number and option_number values.

The only wrinkle on the solution is if certain option numbers were not chosen. You cannot count what's not there, if you're using an INNER JOIN; a LEFT OUTER JOIN should be used instead. But I cannot give you a sample query because I don't know what your three tables look like.