I need to select alphabetically the first customer. So, first I have to sort the table customer on customer_name...
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and then select the first among them. I know Rownum does not work.
My Oracle version is 8.0.6. The following query is also not working:
Select customer_id, customer_name, phone from (select customer_id, customer_name, phone from customer order by customer_name) where rownum <=1.
The query you are trying to run won't work because that syntax is not supported until 8i. So in 8.0.6 you'll need to do what you need in a function something like the following:
create function get_first_alpha_cust return number as cursor cust_cursor is select customer_id from customer order by customer_name; cust_record customer_cursor%rowtype; begin open cust_cursor; for i in 1..1 loop fetch cust_cursor into cust_record; RETURN (cust_record.customer_id); end loop; close cust_cursor; end; /This function could then be called to get the customer_id of the first alphabetically sorted customer. Of course, you can tweak the function to return whatever you want... but hopefully this will get you started!
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