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# GROUP BY multiple columns

## My table structure is empid, category, col1, col2, amount. I would like to get the results as total of amounts for the col1 and col2 combinations, with a particular category.

Hi, my table structure is empid, category, col1, col2, amount. I have five records in this way:

```empid category  col1 col2 amount
1   categoryA   1   10   2.5
1   categoryB   1   10   3.4
1   categoryC   2   11   1.1
1   categoryD   2   11   1.2
1   categoryE   2   11   1.3```

I would like to get the results as total of amounts for the col1 and col2 combinations, with a particular category, like this:

```empid category   total
1   categoryA   5.9 (=2.5+3.4)
1   categoryD   3.6 (=1.1+1.2+1.3)```

The values categoryA and categoryD are predefined, which I should retrieve. Could you please help me with how to do that?

Since you want totals for every combination of col1 and col2, the query involves a multiple-column GROUP BY:

```select empid
, something as category
, sum(amount) as total
from yourtable
group
by empid
, col1
, col2```

The only thing left to figure out is how to pick the correct value of the category column from within each empid/col1/col2 group. What does "predefined" mean? Does each empid/col1/col2 have to have one of those two values?

If so, this might be one way to accomplish it:

```select empid
, max(case when category
in ('categoryA','categoryD')
then category
else null end) as category
, sum(amount) as total
from yourtable
group
by empid
, col1
, col2
having sum(case when category
in ('categoryA','categoryD')
then 1
else 0 end) > 0 ```

If that's not what you want, do please ask a further question.

This was last published in January 2007

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